Need an equation....
Jan. 26th, 2004 06:11 pm![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png)
Here's a math puzzle that I'd like a solution to -- having an answer to it would make a fairly key part of my thesis work much easier.
I need an function z=f(x, y) for a surface in three-space with the following characteristics:
That, as it stands, is the easy part; it suffices to explain the general character of what I'm looking for. I have one final requirement, which makes this a far more difficult problem:
Suggestions welcomed. Needless to say, a proof that a solution does not exist will also be useful.
I need an function z=f(x, y) for a surface in three-space with the following characteristics:
- The surface is, essentially, a bump; it has a finite maximum at (x,y) = (0,0), and decreases monotonically from there down to zero as the radius increases.
- The surface is defined and continuous everywhere.
- The first-order derivatives of the surface are defined and continuous everywhere, specifically including the origin.
- The surface is radially symmetric; it can be expressed exactly as z=g(x2+y2).
- The surface has compact support; there exists some radius R such that, for x2+y2>R, z=0.
That, as it stands, is the easy part; it suffices to explain the general character of what I'm looking for. I have one final requirement, which makes this a far more difficult problem:
- The integral of this function f over any given rectangle in xy-space must have a relatively simple closed-form solution. Integrals involving special functions (e.g., Bessel functions) are acceptable if there exists a simple and accurate numerical algorithm for computing them.
Suggestions welcomed. Needless to say, a proof that a solution does not exist will also be useful.
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Date: 2004-01-26 11:17 pm (UTC)I'm a friend of Aga's.
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Date: 2004-01-26 11:22 pm (UTC)no subject
Date: 2004-01-26 11:25 pm (UTC)write "for x2 + y2 <= 0"?
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Date: 2004-01-26 11:34 pm (UTC)no subject
Date: 2004-01-26 11:36 pm (UTC)(I need to do something about this bad habit I have of hijacking other people's posts. *g*)
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Date: 2004-01-26 11:42 pm (UTC)Hey, the hijack of my feeesheee post wasn't entirely you.
It wasn't even mostly you!
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Date: 2004-01-26 11:45 pm (UTC)It's so cozy, having everyone to talk to at 3 in the morning. (Well, Brooks doesn't get the virtu points because it's only midnight for him, but still.)
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Date: 2004-01-26 11:48 pm (UTC)And I'm not cleaning the bathtub.
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Date: 2004-01-26 11:58 pm (UTC)no subject
Date: 2004-01-27 12:00 am (UTC)Section 104 is perturbingly exact in its four hundred wordsness.
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Date: 2004-01-27 12:08 am (UTC)Last time I cleaned a bathtub, though, I mostly used an old sponge. Also salad oil and dish soap, but that's a different story -- a story of gooey soap scum that resisted all commercial cleansers I had to hand, to be specific, but the salad oil got it off reasonably nicely, and then the dish soap and hot water did quite well at getting the salad oil off.
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Date: 2004-01-27 12:11 am (UTC)There's enough crud (much of it my hair) in/on the tub that I would really like to be able to scrape it off and throw it away without having to think about it.
*ponders at 105 and whether she's awake enough to write it*
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Date: 2004-01-27 12:19 am (UTC)I think I'm going to sleep pretty soon, though, as I need to be up reasonably early tomorrow....
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Date: 2004-01-27 12:23 am (UTC)no subject
Date: 2004-01-27 12:25 am (UTC)no subject
Date: 2004-01-27 12:29 am (UTC)Agh.
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Date: 2004-01-27 05:20 am (UTC)no subject
Date: 2004-01-26 11:54 pm (UTC)no subject
Date: 2004-01-27 05:01 am (UTC)no subject
Date: 2004-01-26 11:38 pm (UTC)